JavaScript Notes
Solve JavaScript object programs: CRUD operations, merge, filter, transform, group by, frequency counter, nested access, and common coding interview problems with solutions.
How to Use This Guide
Each program here follows a pattern:
- Problem — what you need to build
- Approach — the logic / strategy
- Solution — clean, commented code
- Output — verified result
- Variation — a twist to deepen understanding
Program 2 — Invert Key-Value Pairs
{
OK: '200',
'Not Found': '404',
'Internal Server Error': '500',
Created: '201'
}Program 3 — Merge Multiple Objects
// Merge n objects, later values override earlier ones
const base = { theme: "light", lang: "en", fontSize: 14 };
const userPref = { theme: "dark", fontSize: 18 };
const adminPref = { lang: "hi", debug: true };
const merged = Object.assign({}, base, userPref, adminPref);
// Or with spread:
const merged2 = { ...base, ...userPref, ...adminPref };
console.log(merged);{ theme: 'dark', lang: 'hi', fontSize: 18, debug: true }Program 4 — Filter Object Properties
{ Alice: 88, Charlie: 95 }Program 5 — Transform Object Values
{ apple: 45, mango: 72, banana: 27, grapes: 108 }Program 6 — Frequency Counter (Word/Character Count)
{ JS: 4, Python: 2, Java: 1, Ruby: 1 }
Winner: JS with 4 votesProgram 7 — Group By (Array of Objects → Grouped Object)
{
Engineering: [ 'Alice', 'Charlie', 'Eve' ],
Marketing: [ 'Bob', 'Diana' ]
}Program 8 — Deep Clone an Object
Original: Priya Delhi [ 88, 92, 75 ] Clone: Tara Mumbai [ 88, 92, 75, 99 ]
Program 9 — Check if Two Objects are Equal
true false false
Program 10 — Flatten a Nested Object
{
'user.name': 'Ravi',
'user.address.city': 'Bangalore',
'user.address.pincode': 560001,
role: 'admin'
}Program 11 — Pick & Omit Properties
{ id: 1, name: 'Neha', email: 'neha@x.com' }
{ id: 1, name: 'Neha', email: 'neha@x.com' }Program 12 — Object Difference (What Changed?)
Changes: { age: 26, city: 'Mumbai' }Program 13 — Build Object from Two Arrays
{ name: 'Priya', age: 23, city: 'Pune', role: 'developer' }Program 14 — Accumulate Object from Array (Reduce Pattern)
{
A: [ 'Alice' ],
C: [ 'Bob' ],
B: [ 'Charlie', 'Eve' ],
F: [ 'Diana' ]
}Common Patterns Summary
| Task | Method / Pattern |
|---|---|
| Count properties | Object.keys(obj).length |
| Iterate key-value pairs | Object.entries(obj).forEach(...) |
| Filter properties | Object.fromEntries(Object.entries(obj).filter(...)) |
| Transform values | Object.fromEntries(Object.entries(obj).map(...)) |
| Merge objects | { ...obj1, ...obj2 } or Object.assign({}, ...) |
| Clone shallow | { ...obj } |
| Clone deep | structuredClone(obj) |
| Group array of objects | arr.reduce((acc, item) => ...) |
| Frequency counter | arr.reduce((acc, item) => { acc[item]++ ... }) |
| Invert key-value | Object.fromEntries(entries.map(([k,v]) => [v,k])) |
Interview Questions 🎯
Q1. How do you count the number of properties in an object? > Object.keys(obj).length returns the count of own enumerable properties.
Q2. How do you merge two objects with conflict resolution? > Use spread: { ...defaults, ...overrides } — the last object's values win for conflicting keys.
Q3. How do you clone an object deeply? > structuredClone(obj) (ES2022) for a full deep clone. JSON.parse(JSON.stringify(obj)) for simple objects (loses functions, dates as objects, etc.).
Q4. How do you filter an object's properties by value? > Object.fromEntries(Object.entries(obj).filter(([, v]) => condition(v)))
Q5. What is the frequency counter pattern? > Using reduce to count occurrences: arr.reduce((acc, item) => { acc[item] = (acc[item] || 0) + 1; return acc; }, {}).
Q6. How do you compare two objects for equality? > === compares references, not values. For value equality, use JSON.stringify(a) === JSON.stringify(b) (simple), or write a recursive deepEqual function (robust).
Q7. How do you convert an array of [key, value] pairs to an object? > Object.fromEntries(array).
Key Takeaways 🏁
Object.entries()+Object.fromEntries()is the most versatile filter/transform pipelinereducewith an object accumulator is the pattern for frequency counting and grouping- Spread
{ ...a, ...b }merges objects with last-wins conflict resolution structuredClone()is the modern way to deep clone any object===never works for object value comparison — build or use adeepEqualfunction- The frequency counter and group-by patterns appear constantly in coding interviews
Exam Focus
Revise definitions, diagrams, examples, and short-answer points for JavaScript Object Programs - Practice Problems with Solutions.
Interview Use
Prepare one clear explanation, one practical example, and one common mistake for this JavaScript Master Course topic.
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