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Force between two point charges: F = kq₁q₂/r² where k = 9×10⁹ Nm²/C²
Electric Field: E = F/q = kQ/r² (field due to point charge)
Electric Field Lines Rules:
Gauss's Law: ΦE = q_enclosed/ε₀
Potential: V = W/q = kQ/r (unit: Volt) Relation: E = -dV/dr (E is negative gradient of V)
Capacitance: C = Q/V (unit: Farad) Parallel plate capacitor: C = ε₀A/d With dielectric: C = Kε₀A/d (K = dielectric constant)
Series: 1/C = 1/C₁ + 1/C₂ Parallel: C = C₁ + C₂
Energy stored: U = ½CV² = Q²/2C = ½QV
Ohm's Law: V = IR, J = σE (microscopic form) Resistivity: ρ = RA/L; varies with temperature: ρₜ = ρ₀(1 + αt)
Kirchhoff's Laws:
Wheatstone Bridge: P/Q = R/S (balanced condition) Meter Bridge: R/S = l/(100-l)
EMF and Internal Resistance: Terminal voltage V = E - Ir (discharging), V = E + Ir (charging)
Biot-Savart Law: dB = μ₀/4π × Idl sinθ/r² Magnetic field due to long wire: B = μ₀I/2πr Solenoid: B = μ₀nI (n = turns per unit length)
Force on current-carrying conductor: F = BIL sinθ Torque on current loop: τ = NIAB sinθ = MB sinθ
Faraday's Laws:
Self-Inductance: ε = -L(dI/dt), Energy = ½LI² Mutual Inductance: ε₂ = -M(dI₁/dt)
Transformer: V₁/V₂ = N₁/N₂ = I₂/I₁
Snell's Law: n₁sinθ₁ = n₂sinθ₂ Total Internal Reflection: when θ > critical angle (sinθc = n₂/n₁) Applications: optical fibre, diamond, mirage
Lenses:
Waveoptics:
Diffraction: single slit, first minima at sinθ = λ/a
Polarization: only transverse waves can be polarized Malus's law: I = I₀cos²θ
Bohr's Model:
Radioactivity:
Half-life: t₁/₂ = 0.693/λ Decay law: N = N₀e^(-λt)
Semiconductors:
| Feature | Intrinsic | n-type | p-type | |---|---|---|---| | Dopant | None | Pentavalent (P, As) | Trivalent (Al, B) | | Majority carriers | holes = electrons | Electrons | Holes | | Minority carriers | — | Holes | Electrons |
p-n Junction:
Rectifier: Half-wave (one diode) or Full-wave (4 diodes/bridge) Transistor: NPN or PNP; current amplifier
Q1 (2023): Two charges 4μC and -4μC are 20cm apart. Find electric field at midpoint. Both fields point in same direction at midpoint (both towards -charge). E_each = kQ/r² = 9×10⁹ × 4×10⁻⁶ / (0.1)² = 3.6×10⁶ N/C E_total = 7.2×10⁶ N/C
Q2 (2023): An ac source 200V, 50Hz is connected to 20Ω resistor. Find rms current. I_rms = V_rms/R = 200/20 = 10 A
Q3 (2022): In Young's experiment, fringe width is 0.5mm. If distance is doubled, new fringe width? β = λD/d → β is proportional to D → new β = 1.0 mm
Q4 (2024): Find the de Broglie wavelength of electron with KE = 100eV. λ = h/√(2mE) = 6.63×10⁻³⁴/√(2 × 9.1×10⁻³¹ × 100×1.6×10⁻¹⁹) ≈ 1.23 Å
Complete Class 12 Physics notes — electrostatics, current electricity, magnetism, electromagnetic induction, optics, modern physics, and semiconductors with solved CBSE PYQs.
76 pages · 3.8 MB · Updated 2026-03-11
Electrostatics (Unit 1, 15 marks), Current Electricity (Unit 1, 7 marks), Optics (Unit 6, 14 marks), and Modern Physics (Unit 9, 12 marks) are highest priority.
Write all given data clearly, state the formula, substitute values with units, calculate, and always write the final answer with unit. Show all steps for full marks.
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